Physics Question - Circular Motion

For a particle of uniform circular motion, the acceleration \(\vec{a}\) at point \(P(R,\theta)\) on a circle of radius \(R\) is

(Here \(\theta\) is measured from the \(x\)-axis).

[AIEEE - 2010]

Options:

(1) \(\dfrac{v^2}{R} \hat{i} + \dfrac{v^2}{R} \hat{j}\)

(2) \(-\dfrac{v^2}{R}\cos\theta \hat{i} + \dfrac{v^2}{R}\sin\theta \hat{j}\)

(3) \(-\dfrac{v^2}{R}\sin\theta \hat{i} + \dfrac{v^2}{R}\cos\theta \hat{j}\)

(4) \(-\dfrac{v^2}{R}\cos\theta \hat{i} - \dfrac{v^2}{R}\sin\theta \hat{j}\)